Version 4
SHEET 1 940 680
WIRE -512 -32 -624 -32
WIRE -384 -32 -432 -32
WIRE -704 -16 -784 -16
WIRE -544 0 -624 0
WIRE -208 0 -208 -32
WIRE -784 80 -784 -16
WIRE -208 112 -208 80
WIRE -1056 128 -1072 128
WIRE -832 128 -1056 128
WIRE -688 128 -736 128
WIRE -544 128 -544 0
WIRE -544 128 -608 128
WIRE -464 128 -544 128
WIRE -336 128 -336 112
WIRE -336 128 -384 128
WIRE -544 144 -544 128
WIRE -1072 160 -1072 128
WIRE -208 208 -208 192
WIRE -112 208 -208 208
WIRE -208 224 -208 208
WIRE -1072 256 -1072 240
WIRE -784 288 -784 176
WIRE -336 288 -336 128
WIRE -336 288 -784 288
WIRE -208 320 -208 288
FLAG -1072 256 0
FLAG -1056 128 Vin
FLAG -544 144 i[c1]
FLAG -336 112 v[c1]
FLAG -384 -32 0
FLAG -208 320 0
FLAG -112 208 Vc2
FLAG -208 -32 Vin
SYMBOL int -400 128 R0
SYMATTR InstName X4
SYMATTR SpiceLine k={1/C}
SYMATTR Value2 y0=-2
SYMBOL voltage -1072 144 R0
WINDOW 123 0 0 Left 0
WINDOW 39 0 0 Left 0
WINDOW 3 -12 186 Left 0
SYMATTR InstName V1
SYMATTR Value PULSE(-2 5 0.5m 1u 1u 5m 10m 1)
SYMBOL int -624 128 R0
SYMATTR InstName X3
SYMATTR SpiceLine k={1/L}
SYMBOL SUM3 -784 128 R0
WINDOW 39 64 53 Right 0
SYMATTR Value2 Limit=10G
SYMATTR SpiceLine k1=-1 k2=1 k3=-1
SYMATTR InstName U3
SYMBOL MUL2 -656 -16 M0
SYMATTR InstName U4
SYMBOL voltage -528 -32 M90
WINDOW 0 -32 56 VBottom 0
WINDOW 3 32 56 VTop 0
SYMATTR InstName V2
SYMATTR Value {R}
SYMBOL ind -224 96 R0
SYMATTR InstName L2
SYMATTR Value {L}
SYMBOL cap -224 224 R0
SYMATTR InstName C2
SYMATTR Value {C}
SYMBOL res -224 -16 R0
SYMATTR InstName R1
SYMATTR Value {R}
TEXT -648 328 Left 0 !.tran 0 15m 0 10n startup
TEXT -696 248 Left 0 !.param L=100m C=1u R=100
TEXT -112 144 Left 0 !.ic V(C2)=-2 I(L2)=0
TEXT -1080 -344 Left 0 ;"Analog Computer" Simulation
TEXT -1080 -152 Left 0 ;Equations:
TEXT -1064 -112 Left 0 ;L*di[c1]/dt = Vin-(i[c1]*R+v[c1])
TEXT -1064 -80 Left 0 ;C*dV[c1]/dt = i[c1]
TEXT -536 -352 Left 0 ;Note1:  Change y0=-2 to y0=0   and   V(C2)=-2 to V(C2)=0 \n             Which solution is right ? First or the second ? :)
TEXT -536 -280 Left 0 ;Note2:  In the Analog Model the Resitor is defined\n             as a Voltage source !
TEXT -536 -208 Left 0 ;Note3:  Sum3 and INT has built in Limitation of Output (Default +/-10G)\n             There is Hi and Lo limit (Default Hi=+Limit Lo=-Limit\n              It is possible to define abs(Hi) < > abs(Lo) where Hi > Lo\n              Example:  Hi=5  Lo=-3
TEXT -1096 -296 Left 0 ;Peter Kapas, Oct. 2009\ne-mail: pkapas@sbcglobal.net
TEXT -752 392 Left 0 ;Math Model
TEXT -232 392 Left 0 ;LTspice Model
TEXT -752 424 Left 0 ;The Subcircuits are in BLDCSupport.LIB
RECTANGLE Normal -744 -328 -1096 -360
RECTANGLE Normal -728 -64 -1080 -128